Right, that’s exactly what supertype does — it doesn’t accept additional properties. | by Roman Krivtsov

Not sure it’s true that $Shape<T> is a supertype of T.
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Asad S
Roman Krivtsov
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1 min read·
Sep 26, 2017
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Right, that’s exactly what supertype does — it doesn’t accept additional properties.
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Written by Roman Krivtsov701 Followers
·163 Following
Data and Cloud Architect
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